• # question_answer The dimensions of a field are 20 m by 9 m. A pit 10 m long, 4.5 m wide and 3 m deep is dug in one corner of the field and the earth removed has been evenly spread over the remaining area of the field. What will be the rise in the height of field as a result of this operation? A)  1 mB)  2 m         C)  3 m                             D)  4 m

(a): Volume of mud dug out $=10\times 4.5\times 3$$=135\,{{m}^{3}}$ Let the remaining ground rise by = ?h? m Then $\{(20\times 9)-(10\times 4.5)\}h=135$ $135\,h=135\Rightarrow h=1\text{ }m$