10th Class Mathematics Surface Areas and Volumes Question Bank Surface Area and Volume (Mensuration)

  • question_answer The dimensions of a field are 20 m by 9 m. A pit 10 m long, 4.5 m wide and 3 m deep is dug in one corner of the field and the earth removed has been evenly spread over the remaining area of the field. What will be the rise in the height of field as a result of this operation?

    A)  1 m

    B)  2 m         

    C)  3 m                             

    D)  4 m

    Correct Answer: A

    Solution :

    (a): Volume of mud dug out \[=10\times 4.5\times 3\]\[=135\,{{m}^{3}}\] Let the remaining ground rise by = ?h? m Then \[\{(20\times 9)-(10\times 4.5)\}h=135\] \[135\,h=135\Rightarrow h=1\text{ }m\]                          

adversite


You need to login to perform this action.
You will be redirected in 3 sec spinner