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JEE Main & Advanced Physics Simple Harmonic Motion Question Bank Superposition of S H M and Resonance

  • question_answer
    The displacement of a particle varies according to the relation x = 4(cospt + sinpt). The amplitude of the particle is                                                                                               [AIEEE 2003]

    A)            8    

    B)            ? 4

    C)            4    

    D)            \[4\sqrt{2}\]

    Correct Answer: D

    Solution :

                       For given relation Resultant amplitude \[=\sqrt{{{4}^{2}}+{{4}^{2}}}=4\sqrt{2}\]


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