A) 1
B) 2
C) 3
D) 0
Correct Answer: C
Solution :
\[{{C}_{2}}{{H}_{2}}B{{r}_{2}}\] Has three isomers. (1) \[\underset{1,\,2\text{-dibromoethene}}{\mathop{\underset{(cis)}{\mathop{\underset{{}}{\mathop{H-\underset{Br}{\mathop{\underset{|\,\,\,}{\mathop{C\,}}\,}}\,=\underset{Br}{\mathop{\underset{|\,\,\,}{\mathop{C\,}}\,}}\,-H}}\,}}\,}}\,\] (2) \[\underset{\text{1, 2-dibromoethene}}{\mathop{\underset{\text{(Trans)}}{\mathop{\underset{{}}{\mathop{\underset{Br\,\,\,}{\mathop{\underset{|\,\,\,\,}{\mathop{CH}}\,}}\,=\overset{Br}{\mathop{\overset{|\,\,\,\,}{\mathop{CH}}\,}}\,}}\,}}\,}}\,\] (3) \[\underset{\text{1,1-dibromoeth}\,\text{ene}}{\mathop{C{{H}_{2}}=C<_{Br}^{Br}}}\,\]
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