A) 3
B) 4
C) 5
D) 6
Correct Answer: D
Solution :
\[{{C}_{4}}{{H}_{10}}O\] have six isomers are possible 1. \[\underset{\text{Butan-1-ol}}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}-OH}}\,\] 2. \[\underset{\text{Butan-2-ol}}{\mathop{C{{H}_{3}}-C{{H}_{2}}-\underset{OH}{\mathop{\underset{|\,\,\,\,}{\mathop{CH}}\,}}\,-C{{H}_{3}}}}\,\] 3. \[C{{H}_{3}}-\underset{OH}{\overset{H}{\mathop{\underset{|\,\,\,}{\overset{|\,\,}{\mathop{{{C}^{*}}}}}\,}}}\,-COOH\] 4. \[\underset{2-\text{Methyl-propan-2-ol}}{\mathop{C{{H}_{3}}-\underset{OH}{\overset{C{{H}_{3}}}{\mathop{\underset{|\,\,\,\,\,\,}{\overset{|\,\,\,\,\,\,\,}{\mathop{C\,-\,}}}\,}}}\,C{{H}_{3}}}}\,\] 5. \[\underset{\text{Methyl}\,\text{propyl}\,\text{ether}}{\mathop{C{{H}_{3}}-O-{{C}_{3}}{{H}_{7}}}}\,\] 6. \[\underset{\text{Diethyl}\,\text{ether}}{\mathop{{{C}_{2}}{{H}_{5}}-O-{{C}_{2}}{{H}_{5}}}}\,\]
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