A) \[DC{{H}_{2}}C{{H}_{2}}C{{H}_{2}}Cl\]
B) \[C{{H}_{3}}C{{H}_{2}}CHDCl\]
C) \[C{{H}_{3}}CHDC{{H}_{2}}C{{H}_{2}}Cl\]
D) \[C{{H}_{2}}CHClC{{H}_{2}}D\]
Correct Answer: A
Solution :
\[DC{{H}_{2}}-C{{H}_{2}}-C{{H}_{2}}-Cl\] Others are chiral \[C{{H}_{3}}-C{{H}_{2}}-\overset{H\,\,\,\,}{\mathop{\overset{|\,\,\,\,\,}{\mathop{\underset{Cl}{\mathop{\underset{|\,\,\,\,\,}{\mathop{{{C}^{*}}}}\,}}\,}}\,}}\,-D\]; \[C{{H}_{3}}-\underset{D\,\,}{\overset{H\,\,}{\mathop{\underset{|\,\,\,\,}{\overset{|\,\,\,\,}{\mathop{{{C}^{*}}}}}\,}}}\,-C{{H}_{2}}-C{{H}_{2}}-Cl\] \[C{{H}_{3}}-\underset{Cl\,\,}{\overset{H\,\,}{\mathop{\underset{|\,\,\,\,}{\overset{|\,\,\,\,}{\mathop{{{C}^{*}}}}}\,}}}\,-C{{H}_{2}}D\]
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