A) 1
B) 2
C) 3
D) 4
Correct Answer: B
Solution :
\[COOH-\underset{OH\,}{\overset{C{{H}_{3}}}{\mathop{\underset{|\,\,\,\,\,\,\,}{\overset{|\,\,\,\,\,\,\,\,}{\mathop{{{C}^{*}}\,-\,}}}\,}}}\,C{{H}_{2}}-C{{H}_{3}}\] One chiral centre. Therefore two forms are possible.
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