JEE Main & Advanced Physics Wave Mechanics Question Bank Stationary Waves

  • question_answer
    The following equations represent progressive transverse waves \[{{Z}_{1}}=A\cos (\omega \,t-kx)\], \[{{Z}_{2}}=A\cos (\omega \,t+kx)\], \[{{Z}_{3}}=A\cos (\omega \,t+ky)\] and \[{{Z}_{4}}=A\cos (2\omega \,t-2ky)\]. A stationary wave will be formed by superposing [MP PET 1993]

    A)            \[{{Z}_{1}}\] and \[{{Z}_{2}}\]                                           

    B)            \[{{Z}_{1}}\] and \[{{Z}_{4}}\]

    C)            \[{{Z}_{2}}\] and \[{{Z}_{3}}\]                                           

    D)            \[{{Z}_{3}}\] and \[{{Z}_{4}}\]

    Correct Answer: A

    Solution :

                 When two waves of equal frequency and travelling in  opposite direction superimpose, then the stationary wave is produced. Hence Z1 and Z2 produces stationary wave.


You need to login to perform this action.
You will be redirected in 3 sec spinner