JEE Main & Advanced Physics Wave Mechanics Question Bank Stationary Waves

  • question_answer
    Equation of a stationary wave is \[y=10\sin \frac{\pi x}{4}\cos 20\pi t.\] Distance between two consecutive nodes is  [MP PMT 2002]

    A)            4    

    B)            2

    C)            1    

    D)            8

    Correct Answer: A

    Solution :

                         On comparing the given equation with standard equation  \[\frac{2\pi }{\lambda }=\frac{\pi }{4}\Rightarrow \lambda =8\] Hence distance between two consecutive nodes \[\frac{\lambda }{2}=4\]


You need to login to perform this action.
You will be redirected in 3 sec spinner