JEE Main & Advanced Physics Wave Mechanics Question Bank Stationary Waves

  • question_answer
    The distance between the nearest node and antinode in a stationary wave is [MP PET 1984; CBSE PMT 1993; AFMC 1996; RPET 2002]

    A)            l    

    B)            \[\frac{\lambda }{2}\]

    C)            \[\frac{\lambda }{4}\]      

    D)            2l

    Correct Answer: C

    Solution :

                         The distance between the nearest node and antinode in a stationary wave is \[\frac{\lambda }{4}\]


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