JEE Main & Advanced Mathematics Complex Numbers and Quadratic Equations Question Bank Square root, Representation and Logarithm of complex numbers

  • question_answer
    \[{{(-1+i\sqrt{3})}^{20}}\] is equal to [RPET 2003]

    A) \[{{2}^{20}}{{(-1+i\sqrt{3})}^{20}}\]

    B) \[{{2}^{20}}{{(1-i\sqrt{3})}^{20}}\]

    C) \[{{2}^{20}}{{(-1-i\sqrt{3})}^{20}}\]

    D) None of these

    Correct Answer: D

    Solution :

    Let\[z=-1+i\sqrt{3}\], \[r=\sqrt{1+3}=2\] \[\theta ={{\tan }^{-1}}\left( \frac{\sqrt{3}}{-1} \right)=\frac{2\pi }{3}\] \[\therefore \,z=2\,\left( \cos \frac{2\pi }{3}+i\sin \frac{2\pi }{3} \right)\] \[\therefore \,\,{{(z)}^{20}}={{\left[ 2\left( \cos \frac{2\pi }{3}+i\sin \frac{2\pi }{3} \right) \right]}^{20}}\] \[={{2}^{20}}{{\left( \cos \frac{2\pi }{3}+i\sin \frac{2\pi }{3} \right)}^{20}}\]\[={{2}^{20}}{{\left( -\frac{1}{2}+i\frac{\sqrt{3}}{2} \right)}^{20}}\].


You need to login to perform this action.
You will be redirected in 3 sec spinner