question_answer

Use the information given in the diagram to find the value of x.

A)  \[3\sqrt{5}\]     

B)  \[6\sqrt{5}\]     

C)  \[2\sqrt{5}\]                 

D)  \[5\sqrt{5}\]

Correct Answer: D

Solution :

(d): Join BD IN \[\Delta \,ABD,BD=\sqrt{{{20}^{2}}+{{15}^{2}}}=25\] IN \[\Delta BCD,\sqrt{{{x}^{2}}4{{x}^{2}}}={{25}^{2}}\] \[=\sqrt{5x}=25\] \[x=\frac{25}{\sqrt{5}},=5\sqrt{5}.\]