• # question_answer If $\mathbf{x}=\sqrt{100}$, then find the value of $\frac{{{x}^{3}}+{{x}^{2}}}{x}$ A)  120                             B)  100C)  110D)  none of these

(c): $x=10\Rightarrow \frac{{{x}^{3}}+{{x}^{2}}}{x}=\frac{1000+100}{100}$ $=\frac{1100}{100}=110$