• # question_answer 20) If $\sqrt{1+\frac{25}{144}}=1+\frac{p}{12}$, then find the value of p for which this is satisfied. A)  3                                B)  1 C)  -1                               D)  2

(b): $1+\sqrt{\frac{25}{144}}=\sqrt{\frac{169}{144}}=\frac{13}{12}$ $\Rightarrow \frac{13}{12}-1=\frac{1}{12}$ $\Rightarrow \frac{1}{12}=\frac{p}{12}\Rightarrow p=1$