A) \[{{f}_{1}}=\sqrt{2}{{f}_{2}}\]
B) \[{{f}_{1}}={{f}_{2}}\]
C) \[{{b}^{2}}<4ac\]
D) \[{{f}_{2}}=\sqrt{2}{{f}_{1}}\]
Correct Answer: D
Solution :
When spring is cut into two equal parts then spring constant of each part will be 2K and so using \[n\propto \sqrt{K}\], new frequency will be \[\sqrt{2}\] times i.e. \[{{f}_{2}}=\sqrt{2}\,{{f}_{1}}\].
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