JEE Main & Advanced Physics Simple Harmonic Motion Question Bank Spring Pendulum

  • question_answer
    Two springs of constant \[{{k}_{1}}\]and \[{{k}_{2}}\]are joined in series. The effective spring constant of the combination is given by                                                                                        [CBSE PMT 2004]

    A)            \[\sqrt{{{k}_{1}}{{k}_{2}}}\]  

    B)            \[({{k}_{1}}+{{k}_{2}})/2\]

    C)            \[{{k}_{1}}+{{k}_{2}}\]     

    D)            \[{{k}_{1}}{{k}_{2}}/({{k}_{1}}+{{k}_{2}})\]

    Correct Answer: D

    Solution :

                       In series combination \[\frac{1}{{{k}_{S}}}=\frac{1}{{{k}_{1}}}+\frac{1}{{{k}_{2}}}=\frac{{{k}_{2}}+{{k}_{1}}}{{{k}_{1}}{{k}_{2}}}\]\[\Rightarrow {{k}_{S}}=\frac{{{k}_{1}}{{k}_{2}}}{{{k}_{1}}+{{k}_{2}}}\].


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