A) \[(1/2\pi )\sqrt{(K/m)}\]
B) \[(1/2\pi )\sqrt{(2K/m)}\]
C) \[(1/2\pi )\sqrt{(3K/m)}\]
D) \[(1/2\pi )\sqrt{(m/K)}\]
Correct Answer: C
Solution :
\[n=\frac{1}{2\pi }\sqrt{\frac{{{K}_{effective}}}{m}}=\frac{1}{2\pi }\sqrt{\frac{(K+2K)}{m}}\]=\[\frac{1}{2\pi }\sqrt{\frac{3K}{m}}\]
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