A) 10 kg
B) 0.98 kg
C) 5 kg
D) 20 kg
Correct Answer: B
Solution :
Using \[F=kx\] \[\Rightarrow 10g=k\times 0.25\Rightarrow k=\frac{10g}{0.25}=98\times 4\] Now \[T=2\pi \sqrt{\frac{m}{k}}\Rightarrow m=\frac{{{T}^{2}}}{4{{\pi }^{2}}}k\] \[\Rightarrow m=\frac{{{\pi }^{2}}}{100}\times \frac{1}{4{{\pi }^{2}}}\times 98\times 4=0.98\ kg\]
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