A) 1.6 kg
B) 3.9 kg
C) 9.6 kg
D) 12.6 kg
Correct Answer: A
Solution :
\[T=2\pi \sqrt{\frac{m}{k}}\]\[\Rightarrow \frac{{{T}_{2}}}{{{T}_{1}}}=\sqrt{\frac{{{m}_{2}}}{{{m}_{1}}}}\]Þ \[\frac{3}{2}=\sqrt{\frac{m+2}{m}}\]\[\Rightarrow \]\[\frac{9}{4}=\frac{m+2}{m}\] \[\Rightarrow m=\frac{8}{5}kg=1.6\ kg\]
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