JEE Main & Advanced Physics Simple Harmonic Motion Question Bank Spring Pendulum

  • question_answer
    The effective spring constant of two spring system as shown in figure will be                                      [RPMT 1999]

    A)            \[{{K}_{1}}+{{K}_{2}}\]     

    B)            \[{{K}_{1}}{{K}_{2}}/{{K}_{1}}+{{K}_{2}}\]

    C)            \[{{K}_{1}}-{{K}_{2}}\]      

    D)            \[{{K}_{1}}{{K}_{2}}/{{K}_{1}}-{{K}_{2}}\]

    Correct Answer: A

    Solution :

                       When external force is applied, one spring gets extended and another one gets contracted by the same distance hence force due to two springs act in same direction. i.e. \[F={{F}_{1}}+{{F}_{2}}\]Þ \[-\,kx=-\,{{k}_{1}}x-{{k}_{2}}x\Rightarrow \]\[k={{k}_{1}}+{{k}_{2}}\]


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