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JEE Main & Advanced Physics Simple Harmonic Motion Question Bank Spring Pendulum

  • question_answer
    A uniform spring of force constant k is cut into two pieces, the lengths of which are in the ratio 1 : 2. The ratio of the force constants of the shorter and the longer pieces is  [Manipal MEE 1995]

    A)            1 : 3                                          

    B)            1 : 2

    C)            2 : 3                                          

    D)            2 : 1

    Correct Answer: D

    Solution :

                       Force constant \[(k)\,\propto \frac{1}{\text{Length of the string (}l\text{)}}\] Þ \[\frac{{{k}_{1}}}{{{k}_{2}}}=\frac{{{l}_{2}}}{{{l}_{1}}}=\frac{2}{1}\]


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