A) \[20\pi \sec \]
B) \[2\pi \sec \]
C) \[2\pi /10\sec \]
D) \[200\pi \sec \]
Correct Answer: C
Solution :
\[\because \] mg = kx Þ \[\frac{m}{k}=\frac{x}{g}\]Þ \[T=2\pi \sqrt{\frac{m}{k}}=2\pi \sqrt{\frac{x}{g}}\] \[=2\pi \sqrt{\frac{9.8\times {{10}^{-2}}}{9.8}}=\frac{2\pi }{10}\]sec
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