A) \[n\]
B) \[m\left( g+\sqrt{\frac{{{\pi }^{2}}}{2}gh} \right)\]
C) \[n/\sqrt{2}\]
D) \[n{{(2)}^{1/2}}\]
Correct Answer: A
Solution :
\[n=\frac{1}{2\pi }\sqrt{\frac{k}{m}}\]Þ\[\frac{n}{{{n}'}}=\sqrt{\frac{k}{m}\times \frac{{{m}'}}{{{K}'}}}\]\[=\sqrt{\frac{k}{m}\times \frac{2m}{2K}}=1\]Þ \[{n}'=n\]
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