A) 16
B) 10
C) 6
D) None of these
Correct Answer: B
Solution :
\[abc\,\left( 1+\sum \frac{1}{a} \right)\,\left| \,\begin{matrix} 1 & \frac{1}{b} & \frac{1}{c} \\ 0 & 1 & 0 \\ 0 & 0 & 1 \\ \end{matrix}\, \right|\] adj \[A=\left[ \begin{matrix} 4 & -2 \\ -3 & 4 \\ \end{matrix} \right]\] \[|adj\,A|\,=(4\times 4)-(-3\times -2)=16-6\] \[|adj\,A|\,\,=10.\]
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