JEE Main & Advanced Mathematics Determinants & Matrices Question Bank Special types of matrices, Transpose, Adjoint and Inverse of matrices

  • question_answer
    If  \[A=\left[ \begin{matrix}    1 & 2  \\    3 & -5  \\ \end{matrix} \right]\], then \[{{A}^{-1}}\]= [MP PET 2002]

    A) \[\left[ \begin{matrix}    -5 & -2  \\    -3 & 1  \\ \end{matrix} \right]\]

    B) \[\left[ \begin{matrix}    \frac{5}{11} & \frac{2}{11}  \\    \frac{3}{11} & -\frac{1}{11}  \\ \end{matrix} \right]\]

    C) \[\left[ \begin{matrix}    -\frac{5}{11} & -\frac{2}{11}  \\    -\frac{3}{11} & -\frac{1}{11}  \\ \end{matrix} \right]\]

    D) \[\left[ \begin{matrix}    5 & 2  \\    3 & -1  \\ \end{matrix} \right]\]

    Correct Answer: B

    Solution :

          \[A=\left[ \,\begin{matrix}    1 & 2  \\    3 & -5  \\ \end{matrix}\, \right]\] \[adj\,A=\left[ \,\begin{matrix}    -5 & -2  \\    -3 & +1  \\ \end{matrix}\, \right]\]      \[|A|=\left| \,\begin{matrix}    1 & 2  \\    3 & -5  \\ \end{matrix}\, \right|=-11\] \[\therefore \,\,{{A}^{-1}}=\frac{1}{11}\left[ \,\begin{matrix}    5 & 2  \\    3 & -1  \\ \end{matrix}\, \right]=\left[ \,\begin{matrix}    5/11 & 2/11  \\    3/11 & -1/11  \\ \end{matrix}\, \right]\].


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