A) \[{{(BA)}^{-1}}\]
B) \[{{B}^{-1}}{{A}^{-1}}\]
C) \[{{A}^{-1}}{{B}^{-1}}\]
D) \[{{(A{B}')}^{-1}}\]
Correct Answer: B
Solution :
Given, Square matrices A and B of same order. We know that if A and B are non-singular matrices of the same orders, then \[{{(AB)}^{-1}}={{B}^{-1}}{{A}^{-1}}.\]
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