JEE Main & Advanced Mathematics Determinants & Matrices Question Bank Special types of matrices, Transpose, Adjoint and Inverse of matrices

  • question_answer
    If \[A=\left( \begin{matrix}    1 & -2 & 1  \\    2 & 1 & 3  \\ \end{matrix} \right)\]and \[B=\left( \begin{matrix}    2 & 1  \\    3 & 2  \\    1 & 1  \\ \end{matrix} \right)\], then \[{{(AB)}^{T}}\]is equal to [RPET 2001]

    A) \[\left( \begin{matrix}    -3 & -2  \\    10 & 7  \\ \end{matrix} \right)\]

    B) \[\left( \begin{matrix}    -3 & 10  \\    -2 & 7  \\ \end{matrix} \right)\]

    C) \[\left( \begin{matrix}    -3 & 7  \\    10 & 2  \\ \end{matrix} \right)\]

    D) None of these

    Correct Answer: B

    Solution :

    \[{{C}_{3}}\to {{C}_{3}}-{{C}_{2}}\] \[{{(AB)}^{T}}=\left( \begin{matrix}    -3 & 10  \\    -2 & 7  \\ \end{matrix} \right)\].


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