A) \[\left[ \begin{matrix} 2 & -5 & 32 \\ 0 & 1 & -6 \\ 0 & 0 & 2 \\ \end{matrix} \right]\]
B) \[\left[ \begin{matrix} -1 & 0 & 0 \\ -5 & -2 & 0 \\ 1 & -6 & 1 \\ \end{matrix} \right]\]
C) \[\left[ \begin{matrix} -1 & 0 & 0 \\ -5 & -2 & 0 \\ 1 & -6 & -1 \\ \end{matrix} \right]\]
D) None of these
Correct Answer: D
Solution :
\[A=\left[ \begin{matrix} 1 & 0 & 0 \\ 5 & 2 & 0 \\ -1 & 6 & 1 \\ \end{matrix} \right]\] \[\Rightarrow \] \[adj\,(A)={{\left[ \begin{matrix} 2 & -5 & 32 \\ 0 & 1 & -6 \\ 0 & 0 & 2 \\ \end{matrix} \right]}^{T}}=\left[ \begin{matrix} 2 & 0 & 0 \\ -5 & 1 & 0 \\ 32 & -6 & 2 \\ \end{matrix} \right]\].
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