10th Class Science Sources of Energy Question Bank Sources of Energy

  • question_answer
    Number of photons emitted in 10 hours by 60 W sodium lamp is \[(\lambda =5893\overset{\circ }{\mathop{A}}\,)\]

    A)  \[\text{6}.\text{4}0\text{ }\times \text{ 1}{{0}^{\text{22}}}\]

    B)  \[\text{6}.\text{4}0\text{ }\times \text{ 1}{{0}^{\text{24}}}\]  

    C)  \[\text{4}.\text{6}0\text{ }\times \text{ 1}{{0}^{\text{22}}}\]

    D)  \[\text{4}.\text{6}0\text{ }\times \text{ 1}{{0}^{\text{24}}}\]

    Correct Answer: B

    Solution :

     Energy of photon,\[E=\frac{hc}{\lambda }\]                 \[=\frac{(6\cdot 63\times {{10}^{-34}})(3\times {{10}^{8}})}{5893\times {{10}^{-10}}}\]                 \[=3.374\times {{10}^{-19}}J\] Number of photons emitted per sec.                 \[=\frac{60}{3.374\times {{10}^{-19}}}\] Number of photons emitted in \[10\] hours                 \[=\frac{60\times 10\times 3600}{3.374\times {{10}^{-19}}}\mathbf{=6}\mathbf{.40\times 1}{{\mathbf{0}}^{\mathbf{24}}}\]\[\]


You need to login to perform this action.
You will be redirected in 3 sec spinner