A) first increase and then decrease
B) first decrease and then increase
C) go on increasing
D) go on decreasing
Correct Answer: A
Solution :
Time period of simple pendulum \[T=2\pi \sqrt{(\frac{l}{g})\propto \sqrt{l}}\]where / is effective length. [i.e distance between centre of suspension and centre of gravity of bob] Initially, centre of gravity is at the centre of sphere. When water leaks the centre of gravity goes down until it is half filled; then it begins to go up and finally it again goes at the centre. That is effective length first increases and then decreases. As \[T\propto \sqrt{l}\], so time period first increases and then decreases.
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