A) \[\frac{\pi }{6},\frac{\pi }{3}\]
B) \[\frac{\pi }{6},\frac{5\pi }{6}\]
C) \[\frac{\pi }{3},\frac{\pi }{4}\]
D) \[\frac{\pi }{2},\pi \]
Correct Answer: B
Solution :
Eliminating\[r\], we get \[\therefore \] \[\sin \theta =\frac{1}{2},\,-\frac{3}{2}\] (rejected) \[\Rightarrow \] \[\theta =\frac{\pi }{6},\,\pi -\frac{\pi }{6}=\frac{5\pi }{6}\].
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