A) \[-\frac{5\pi }{6}\]
B) \[-\frac{4\pi }{6}\]\[\]
C) \[\frac{4\pi }{6}\]
D) \[\frac{5\pi }{6}\]
Correct Answer: B
Solution :
\[\tan \theta =\sqrt{3}=\tan \frac{\pi }{3}\Rightarrow \theta =n\pi +\frac{\pi }{3}\] For \[-\pi <\theta <0\] \[\text{Put}\,\,n=-1\], we get\[\theta =-\pi +\frac{\pi }{3}=\frac{-2\pi }{3}\text{or }\frac{-4\pi }{6}\].
You need to login to perform this action.
You will be redirected in
3 sec
