JEE Main & Advanced Mathematics Trigonometric Equations Question Bank Solution of trigonometrical equations

  • question_answer
    If \[\cos \theta +\cos 2\theta +\cos 3\theta =0\], then the general value of \[\theta \] is [UPSEAT 2003]

    A) \[\theta =2m\pi \pm \frac{2\pi }{3}\]

    B) \[\theta =2m\pi \pm \frac{\pi }{4}\]

    C) \[\theta =m\pi \pm {{(-1)}^{m}}\frac{2\pi }{3}\]

    D) \[x=m\pi +{{(-1)}^{m}}\frac{\pi }{3}\]

    Correct Answer: A

    Solution :

     \[\cos \theta +\cos 2\theta +\cos 3\theta =0\] Þ  \[(\cos \theta +\cos 3\theta )+\cos 2\theta =0\] Þ  \[2\cos 2\theta \cos \theta +\cos 2\theta =0\] Þ  \[\cos 2\theta (2\cos \theta +1)=0\] Þ \[\cos 2\theta =0=\cos \frac{\pi }{2}\] Þ  \[\theta =\frac{\pi }{4}\]Þ \[\theta =2m\pi \pm \frac{\pi }{4}\] or \[\cos \theta =\frac{-1}{2}=\cos \frac{2\pi }{3}\] Þ \[\theta =2m\pi \pm \frac{2\pi }{3}\].


You need to login to perform this action.
You will be redirected in 3 sec spinner