JEE Main & Advanced Mathematics Trigonometric Equations Question Bank Solution of trigonometrical equations

  • question_answer
    General solution of \[\tan 5\theta =\cot 2\theta \] is  [Karnataka CET 2000; Pb. CET 2001]

    A) \[\theta =\frac{n\pi }{7}+\frac{\pi }{14}\]

    B)  \[\theta =\frac{n\pi }{7}+\frac{\pi }{5}\]

    C) \[\theta =\frac{n\pi }{7}+\frac{\pi }{2}\]

    D) \[\theta =\frac{n\pi }{7}+\frac{\pi }{3},n\in Z\]

    Correct Answer: A

    Solution :

    \[\tan 5\theta =\tan \left( \frac{\pi }{2}-2\theta  \right)\] \[\Rightarrow \] \[5\theta =n\pi +\frac{\pi }{2}-2\theta \] \[\Rightarrow \] \[7\theta =n\pi +\frac{\pi }{2}\]\[\Rightarrow \] \[\theta =\frac{n\pi }{7}+\frac{\pi }{14}\].


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