JEE Main & Advanced Mathematics Trigonometric Equations Question Bank Solution of trigonometrical equations

  • question_answer
    The  general solution of \[\tan 3x=1\] is[Karnataka CET 1991]

    A) \[n\pi +\frac{\pi }{4}\]

    B) \[\frac{n\pi }{3}+\frac{\pi }{12}\]

    C) \[n\pi \]

    D) \[n\pi \pm \frac{\pi }{4}\]

    Correct Answer: B

    Solution :

    \[\tan 3x=1\Rightarrow \tan 3x=\tan \frac{\pi }{4}\] \[\Rightarrow 3x=n\pi +\frac{\pi }{4}\]\[\Rightarrow \] \[x=\frac{n\pi }{3}+\frac{\pi }{12}\].


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