JEE Main & Advanced Mathematics Trigonometric Equations Question Bank Solution of trigonometrical equations

  • question_answer
    The solution of the equation \[4{{\cos }^{2}}x+6\]\[{{\sin }^{2}}x=5\]  [AI CBSE 1983]

    A) \[x=n\pi \pm \frac{\pi }{2}\]

    B) \[x=n\pi \pm \frac{\pi }{4}\]

    C) \[x=n\pi \pm \frac{3\pi }{2}\]

    D) None of these

    Correct Answer: B

    Solution :

    \[4+2{{\sin }^{2}}x=5\] \[\Rightarrow \] \[{{\sin }^{2}}x=\frac{1}{2}={{\sin }^{2}}\frac{\pi }{4}\Rightarrow x=n\pi \pm \frac{\pi }{4}\].


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