A) \[2n\pi -\frac{\pi }{4}\pm \,\,\alpha \]
B) \[2n\pi +\frac{\pi }{4}\pm \alpha \]
C) \[n\pi -\frac{\pi }{4}\pm \alpha \]
D) \[n\pi +\frac{\pi }{4}\pm \alpha \]
Correct Answer: B
Solution :
\[\sin \theta +\cos \theta =\sqrt{2}\cos \alpha \Rightarrow \cos \left( \theta -\frac{\pi }{4} \right)=\cos \alpha \] \[\Rightarrow \] \[\theta -\frac{\pi }{4}=2n\pi \pm \alpha \Rightarrow \theta =2n\pi +\frac{\pi }{4}\pm \alpha \].
You need to login to perform this action.
You will be redirected in
3 sec
