A) \[2n\pi \pm \frac{\pi }{6}\]
B) \[n\pi \pm \frac{\pi }{6}\]
C) \[2n\pi \pm \frac{\pi }{3}\]
D) \[n\pi \pm \frac{\pi }{3}\]
Correct Answer: D
Solution :
\[\frac{1-\cos 2\theta }{1+\cos 2\theta }=3\]Þ \[\frac{1-(1-2{{\sin }^{2}}\theta )}{1+(2{{\cos }^{2}}\theta -1)}=3\] \[\Rightarrow \] \[{{\tan }^{2}}\theta =3\]\[\Rightarrow \] \[\theta =n\pi \pm \frac{\pi }{3}\].
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