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JEE Main & Advanced Mathematics Complex Numbers and Quadratic Equations Question Bank Solution of quadratic equations and Nature of roots

  • question_answer
    If the roots of the given equation \[2{{x}^{2}}+3(\lambda -2)x+\lambda +4=0\] be equal in magnitude but opposite in sign, then \[\lambda \]=

    A) 1

    B) 2

    C) 3

    D) 2/3

    Correct Answer: B

    Solution :

    Let roots are \[\alpha \]and \[-\alpha \], then sum of the roots \[\alpha +(-\alpha )=\frac{3(\lambda -2)}{2}\Rightarrow 0=\frac{3}{2}(\lambda -2)\]Þ\[\lambda =2\]


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