2. Questions Bank
  3. JEE Main & Advanced
  4. Mathematics
  5. Complex Numbers and Quadratic Equations

JEE Main & Advanced Mathematics Complex Numbers and Quadratic Equations Question Bank Solution of quadratic equations and Nature of roots

  • question_answer
    If the roots of the given equation \[({{m}^{2}}+1){{x}^{2}}+2amx+{{a}^{2}}-{{b}^{2}}=0\] be equal, then

    A) \[{{a}^{2}}+{{b}^{2}}({{m}^{2}}+1)=0\]

    B) \[{{b}^{2}}+{{a}^{2}}({{m}^{2}}+1)=0\]

    C) \[{{a}^{2}}-{{b}^{2}}({{m}^{2}}+1)=0\]

    D) \[{{b}^{2}}-{{a}^{2}}({{m}^{2}}+1)=0\]

    Correct Answer: C

    Solution :

    Roots are equal, then \[{{B}^{2}}-4AC=0\] Þ \[4{{a}^{2}}{{m}^{2}}=4({{m}^{2}}+1)({{a}^{2}}-{{b}^{2}})\] Þ  \[{{a}^{2}}-{{b}^{2}}({{m}^{2}}+1)=0\].


You need to login to perform this action.
You will be redirected in 3 sec spinner