A) \[\frac{4}{5}\]
B) \[\frac{1}{3}\]
C) \[\frac{2}{3}\]
D) \[\frac{4}{3}\]
Correct Answer: C
Solution :
Roots of equation \[4{{x}^{2}}+6px+1=0\] are equal \[\therefore {{B}^{2}}-4AC=0\] Þ \[{{(6p)}^{2}}=4.4.1\]\[\Rightarrow 36{{p}^{2}}=16\]\[\Rightarrow p=2/3\].
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