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JEE Main & Advanced Mathematics Complex Numbers and Quadratic Equations Question Bank Solution of quadratic equations and Nature of roots

  • question_answer
    The value of \[k\] for which the quadratic equation,\[k{{x}^{2}}+1=\]\[kx+3x-11{{x}^{2}}\] has real and equal roots are [BIT Ranchi 1993]

    A) \[-11,-3\]

    B) \[5,\,7\]

    C) \[5,-7\]

    D) None of these

    Correct Answer: C

    Solution :

    The quadratic is \[(k+11){{x}^{2}}-(k+3)x+1=0\] Accordingly, \[{{(k+3)}^{2}}-4(k+11)(1)=0\]Þ \[k=-7,5\].


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