A) Reciprocal and of same sign
B) Reciprocal and of opposite sign
C) Equal in product
D) None of these
Correct Answer: B
Solution :
We have that, if roots of \[a{{x}^{2}}+bx+c=0\]are\[\alpha ,\beta \], then the roots of \[c{{x}^{2}}+bx+a=0\]will be \[\frac{1}{\alpha },\frac{1}{\beta }\] and hence roots of \[c{{x}^{2}}-bx+a=0\]will be\[-\frac{1}{\alpha },-\frac{1}{\beta }\].
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