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JEE Main & Advanced Mathematics Complex Numbers and Quadratic Equations Question Bank Solution of quadratic equations and Nature of roots

  • question_answer
    The roots of the equation \[{{x}^{2}}+2\sqrt{3}x+3=0\]are  [RPET 1986]

    A) Real and unequal  

    B) Rational and equal

    C) Irrational and equal

    D) Irrational and unequal

    Correct Answer: C

    Solution :

    Let \[f(x)={{x}^{2}}+2\sqrt{3}x+3=0\] Then \[x=\frac{-2\sqrt{3}\pm \sqrt{12-12}}{2}\]or\[x=-\sqrt{3}\]. Thus roots are irrational and equal.


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