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JEE Main & Advanced Mathematics Complex Numbers and Quadratic Equations Question Bank Solution of quadratic equations and Nature of roots

  • question_answer
    If the product of the roots of the equation \[2{{x}^{2}}+6x+\] \[{{\alpha }^{2}}+1=0\] is \[-\alpha \], then the value of \[\alpha \] will be

    A) -1

    B) 1

    C) 2

    D) -2

    Correct Answer: A

    Solution :

    According to condition \[\frac{{{\alpha }^{2}}+1}{2}=-\alpha \] Þ \[{{\alpha }^{2}}+2\alpha +1=0\Rightarrow \alpha =-1,-1\].


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