2. Questions Bank
  3. JEE Main & Advanced
  4. Mathematics
  5. Complex Numbers and Quadratic Equations

JEE Main & Advanced Mathematics Complex Numbers and Quadratic Equations Question Bank Solution of quadratic equations and Nature of roots

  • question_answer
    The roots of the equation \[a({{x}^{2}}+1)-({{a}^{2}}+1)x=0\] are

    A) \[a,\frac{1}{a}\]

    B) a, 2a

    C) \[a,\frac{1}{2a}\]

    D) None of these

    Correct Answer: A

    Solution :

    Equation \[a({{x}^{2}}+1)-({{a}^{2}}+1)x=0\] Þ\[a{{x}^{2}}-({{a}^{2}}+1)x+a=0\] Þ \[(ax-1)(x-a)=0\]Þ \[x=a,\frac{1}{a}\].


You need to login to perform this action.
You will be redirected in 3 sec spinner