A) \[y-3=2(x-2)\]
B) \[y-3=(2-\sqrt{3})(x-2)\]
C) \[y-3=(\sqrt{3}-1)(x-2)\]
D) None of these
Correct Answer: B
Solution :
\[y-3=\tan (\theta \pm {{60}^{o}})(x-2)\] As \[\theta ={{135}^{o}},\]So \[y-3=\frac{-1\pm \sqrt{3}}{1\mp (-\sqrt{3})}(x-2)\] i.e., \[y-3=\frac{-1+\sqrt{3}}{\sqrt{3}+1}(x-2)=(2-\sqrt{3})(x-2)\].
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