question_answer

The diagonal passing through origin of a quadrilateral formed by \[x=0,\ y=0,\ x+y=1\] and \[6x+y=3,\] is [IIT 1973]

A)            \[3x-2y=0\]                              

B)            \[2x-3y=0\]

C)            \[3x+2y=0\]                            

D)            None of these

Correct Answer: A

Solution :

           According to the figure, diagonal BD is passing through origin, therefore its equation is given by \[\left( y-\frac{3}{5} \right)=\frac{-(3/5)}{-(2/5)}\left( x-\frac{2}{5} \right)\]                    Þ \[3x-2y=0\].