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JEE Main & Advanced Mathematics Straight Line Question Bank Slope of line, Equation of line in different forms

  • question_answer
    Equation of a line passing through (1, -2) and perpendicular to the line \[3x-5y+7=0\] is                                       [RPET 2003]

    A) \[5x+3y+1=0\]                      

    B) \[3x+5y+1=0\]

    C) \[5x-3y-1=0\]                          

    D) \[3x-5y+1=0\]

    Correct Answer: A

    Solution :

    Equation of a line perpendicular to \[3x-5y+7=0\] is \[5x+3y+\lambda =0\]                                                 ??(i)                    \[\because \] This equation passes through \[(1,\,-2)\]                    \ \[5\times 1+3\times (-2)+\lambda =0\] Þ \[5-6+\lambda =0\]Þ \[\lambda =1\]                    \  Equation is\[5x+3y+1=0\].


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