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JEE Main & Advanced Mathematics Straight Line Question Bank Slope of line, Equation of line in different forms

  • question_answer
    The equation to the straight line passing through the point of intersection of the lines \[5x-6y-1=0\] and \[3x+2y+5=0\] and perpendicular to the line \[3x-5y+11=0\] is  [MP PET 1994]

    A)            \[5x+3y+8=0\]                      

    B)            \[3x-5y+8=0\]

    C)            \[5x+3y+11=0\]                    

    D)            \[3x-5y+11=0\]

    Correct Answer: A

    Solution :

               The point of intersection of \[5x-6y-1=0\]and \[3x+2y+5=0\]is\[(-1,\,-1)\]. Now the line perpendicular to \[3x-5y+11=0\]is \[5x+3y+k=0\], but it passes through \[(-1,-1)\] Þ \[-5-3+k=0\Rightarrow k=8\]                    Hence required line is\[5x+3y+8=0\].


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