A) \[x\sin \theta +y\cos \theta -2a=0\]
B) \[x\cos \theta +y\sin \theta -2a=0\]
C) \[x\sec \theta +y\,\text{cosec}\theta -2a=0\]
D) \[x\,\text{cosec}\theta +y\sec \theta -2a=0\]
Correct Answer: B
Solution :
Using the intercept form of the line \[\frac{x}{2a\sec \theta }+\frac{y}{2a\text{cosec}\theta }=1\Rightarrow x\cos \theta +y\sin \theta =2a\].
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